HLJ 发布于
2018-10-19 11:56:23
294阅读

java生成随机IP

JAVA生成随机IP
有的时候你需要生成一些随机的国内IP进行测试,代码如下
随机生成1000个IP
import java.util.Random;
public class WarnIp {
	public static String getRandomIp() {
		// 需要排除监控的ip范围
		int[][] range = { { 607649792, 608174079 }, // 36.56.0.0-36.63.255.255
				{ 1038614528, 1039007743 }, // 61.232.0.0-61.237.255.255
				{ 1783627776, 1784676351 }, // 106.80.0.0-106.95.255.255
				{ 2035023872, 2035154943 }, // 121.76.0.0-121.77.255.255
				{ 2078801920, 2079064063 }, // 123.232.0.0-123.235.255.255
				{ -1950089216, -1948778497 }, // 139.196.0.0-139.215.255.255
				{ -1425539072, -1425014785 }, // 171.8.0.0-171.15.255.255
				{ -1236271104, -1235419137 }, // 182.80.0.0-182.92.255.255
				{ -770113536, -768606209 }, // 210.25.0.0-210.47.255.255
				{ -569376768, -564133889 }, // 222.16.0.0-222.95.255.255
		};

		Random rdint = new Random();
		int index = rdint.nextInt(10);
		String ip = num2ip(range[index][0] + 
		new Random().nextInt(range[index][1] - range[index][0]));
		return ip;
	}
	/*
	 * 将十进制转换成IP地址
	 */
	public static String num2ip(int ip) {
		int[] b = new int[4];
		String x = "";
		b[0] = (int) ((ip >> 24) & 0xff);
		b[1] = (int) ((ip >> 16) & 0xff);
		b[2] = (int) ((ip >> 8) & 0xff);
		b[3] = (int) (ip & 0xff);
		x = Integer.toString(b[0]) + "." + Integer.toString(b[1]) + "." + 
		Integer.toString(b[2]) + "." + Integer.toString(b[3]);
 
		return x;
	}
	public static void main(String[] args) {
		int count = 10000;
		for (int i = 0; i < count; i++) {
			String randomIp = getRandomIp();
			System.err.println(randomIp);
		}
	}
}
文章来源:http://www.javataotao.com/webmain/news_detail.do?newsid=new20180723161044
最后生成于 2024-06-22 12:03:41
此内容有帮助 ?
0